00:01
I'm thinking that this problem is going to have multiple answers.
00:03
Let me kind of get this down.
00:05
You have 40 .5 degrees across from angle a is sine length a.
00:12
Now what i don't know is it is it a triangle that goes like this? so let me just jot that down.
00:18
I'm going to put the nine over here and then b is 10 .9.
00:23
So to first figure out if you have is make it right triangle and call it h.
00:29
And so what you would have is sine of 40 .5 degrees is equal to h over 10 .9 and that h would then equal 10 .9 times sine of 40 .5 degrees.
00:43
Make sure your calculator is in degree mode.
00:47
So i got to change my mode real quick and then type that in 10 .9 sine of 40 .5 gives me an answer of 7 .0789.
01:01
Okay, that's enough.
01:02
The fact that that's smaller than nine tells me that we have the answer is a.
01:06
There are two triangles and now you can use the law of sines that it would be, i don't know, i want to do this.
01:17
A sine of 40 .5 degrees over nine is equal to sine of angle b over 10 .9.
01:29
And i've done a few of these steps already because i had to multiply that 10 .9 over.
01:34
But then to figure out what angle b is, it would be inverse sine of, let me just write h because that's what it's equal to there.
01:47
So i'll have to write that again.
01:49
So inverse sine of my answer over nine.
01:57
And i got one answer for angle b.
02:00
Let me just write it right here to be 51 .864.
02:04
I don't know where i'm supposed to round.
02:06
Says nearest 10th...