00:01
So for this problem, the first thing that'll note is that, well, we are asked to find the five number summary.
00:06
So we have min, q1, median, q3, and maximum.
00:15
So we can note that with the numbers given, they're actually already arranged in ascending order, so it's not too difficult to find these.
00:24
Specifically, the minimum and the maximum are very easy.
00:27
We can see that the minimum value is 160 and the maximum value is 196.
00:31
Then to find the median, what i'll do is first find the rank of the median by determining the number of data points that we have.
00:42
So i'll note that we have 25 observations, the rank will be 25 plus 1 divided by 2.
00:50
So it would be 26 over 2, which is 13.
00:53
So we have that the median is going to be the 13th measurement in order.
00:58
So i'm going to pause and determine what value that is.
01:01
So we have that the 13th value is going to be 167.
01:07
To find the rank of the first quartile, we take one quarter of 26.
01:15
So let's see here, 26 over 4 gives a result of 6 .5.
01:19
So that means that the first quartile is going to be the average of the 6th and 7th values.
01:25
But we'll find that both x6 and x7 are equal to each other.
01:30
They're both equal to 162.
01:32
So the first quartile is just 162.
01:36
And then for the third quartile, the rank of q3, that's going to be three quarters of 26, or three times 26 over four, which gives a result of 19 .5, suggesting that our third quartile will be the average of the 19th and 20th values.
01:55
So, i'll note that x -19 is equal to 173, x -20 is equal to 117, 76.
02:08
So the midpoint between those two values would be at 174 .5.
02:14
So that gives us our third quartile, 174 .5.
02:19
Now i'm going to pause for a second and swap my background here...