00:01
Here in this problem given the exact neutralization of 15 milliliters of 0 .2500 molar h2so4 solution requires 19 .50 milliliters of the naoh tritane.
00:15
First we have to balance the chemical equation for the reaction between sulfuric acid and naoh.
00:21
Then we have to find out the molarity of the naoh tritane solution.
00:27
First we will write down the equation for the reaction between sulfuric acid and naoh and the products are sodium sulfate na2so4 and water.
00:53
Now we have to balance two na atoms on the right side so we'll place two here.
00:59
Now we have two na atoms on the both sides of the equation, one sulfur atom on the both sides of the equation and here two and here two total four hydrogen atoms on the left side so we'll place two here.
01:15
Now we have four hydrogen atoms on the both sides of the equation.
01:19
Here four plus two oxygen atoms on the left side that is six and here also four plus two six oxygen atoms so this is the balanced equation.
01:31
Now we have to find out the molarity of the naoh solution.
01:36
Here we'll use the formula m1 v1 divided by n1 is equal to m2 v2 divided by n2...