00:01
Hi, here in this given problem out of multiple questions, based upon waves and oscillation, i am solving only the first three.
00:08
Starting with the first, that is question number 15.
00:12
Frequency of the standing wave created on the rope, this is, this will be equal to the vibrator, which is being used to create this stationary wave, means 28 hertz.
00:28
Wave length of the wave, lambda, that is 9.
00:35
5 cm and using the pattern of the wave here these minimum displacement points these are known as nodes and this distance that is equal to half of the wavelength so the distance between the successive nodes that will be actually equal to half of wavelength means 9 .5 by 2 cm means this is 4 .75 centimeter.
01:20
Answer for this problem number 15, then problem number 16, the distance between the second and the fifth nodes, it will be actually equal to three loops, means three times of wavelength, three times of half of wavelength.
01:50
And that is given as 59 centimeters.
01:55
So, using that, we come to know about wavelength, wavelength will be given by two times of 59 by 3.
02:03
Means that is 39 .3 cm.
02:08
Frequency given here, that is 25 hertz.
02:17
So the speed of the sound will be, sorry, speed of the wave in the string will be c is equal to f into lambda.
02:26
F means frequency 25 hertz, wavelength, 30 ,000...