Find the equation of the line that passes through the point (1, 6) and is parallel to the line: 3x + y = 1.
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We can do this by rearranging the equation into slope-intercept form (y = mx + b), where m is the slope: 3r + Sy = l Sy = -3r + l y = (-3/S)r + (l/S) So the slope of the given line is -3/S. Since we want to find the equation of a line that is parallel to this Show more…
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