00:01
Hi, here in this given problem, these two resistors r4 and r5, these are in series first of all, and that is the first series of the circuit.
00:09
So it will be given as rs1 is equal to r4 plus r5.
00:16
Means that is 14 plus 6 oom and that is calculated to be equal to 20 om.
00:24
Now, the right terminal of r5, it is short circuited over here.
00:31
So actually this is, rs 1 that is in parallel with r2.
00:37
So now rs1 is in parallel with r2.
00:50
R2 20 -oom and rs1 that is also 20 -homes.
00:53
So net resistance of this parallel combination, rp, it will be given by 20 by 2 means that is 10 -o.
01:04
Now this parallel combination, this is in series with r1, that is the second series of the circuit r s2, it will be given by 10 plus 10 means that is 20 oom...