15 kg of water is heated from 67°C to 100°C. What is the change in entropy? The specific heat of water is 10 cal/kg·K. Answer in units of cal/K.
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Given: k = 9 x 10^9 Nm^2/C^2 q = 1.6 x 10^-19 C Initial distance, r1 = 2 mm = 2 x 10^-3 m Initial electrostatic energy = k * (q^2) / r1 Initial electrostatic energy = 9 x 10^9 * (1.6 x 10^-19)^2 / 2 x 10^-3 Initial electrostatic energy = 2.304 x 10^-17 J Show more…
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