00:01
Okay, so here we've got a loop of wire with a magnetic field pointing out of the page in the bottom half of it.
00:10
It's changing with time and this is going to induce an emf.
00:13
Part a asks us to calculate this emf.
00:16
This is given by minus the derivative of the magnetic flux with respect to time.
00:20
Now the magnetic flux is given by the magnetic field times the area that the magnetic field is going through.
00:31
Now this is going to be half the total area of the loop because the magnetic field just lies in the bottom half.
00:36
And so this is 3b.
00:38
And therefore the emf is minus 3 times the derivative of b with respect to time, which is just minus 3 times minus 0 .87.
00:47
And this is 2 .61 volts.
00:53
It then asks us for the induced current.
00:55
And for this, we just use oms law.
00:57
So we rearrange v equals ir to have i equals v overall.
01:01
And we plug in the numbers we know, which is 2 .61 from part a, and then we are told in the question that the resistance is 3 .2.
01:08
This gives us 0 .82 amps to two decimal places.
01:16
We're also asked to find the direction...