Question

15. What is the m/v % of a solution containing $2.2 \times 10^{23}$ molecules of $CO_2$ in 100 mL of water? a. 1.61 m/v% b. 3.65 m/v% c. 16.1 m/v% d. 36.5 m/v%

          15. What is the m/v % of a solution containing $2.2 \times 10^{23}$ molecules of $CO_2$ in 100 mL of water?
a. 1.61 m/v%
b. 3.65 m/v%
c. 16.1 m/v%
d. 36.5 m/v%

$15. What is the m/v % of a solution containing $2.2 \times 10^{23}$ molecules of $CO2$ in 100 mL of water? a. 1.61 m/v% b. 3.65 m/v% c. 16.1 m/v% d. 36.5 m/v%$

Added by Albert L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Preeti Kumari

05/28/2022

Step 1

The molarity (M) is the number of moles of solute per liter of solution. We can calculate the molarity using the formula: Molarity (M) = moles of solute / liters of solution Given: Number of molecules of CO₂ = 2.2 x 10^23 Volume of solution = 100 mL = 0.1 Show more…

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