00:01
In this problem, first we're looking at ozonalysis reactions.
00:04
So this is where we have a double bond between carbons.
00:07
We cleave it, and each of those carbons is then doubly bound to oxygen instead.
00:14
So we come in here and break this bond.
00:17
So we have one, two, three, four, five, six carbons.
00:24
And at carbons one and six, we have double bonds.
00:29
And you can draw on the hydrogens, if you would like.
00:32
So this is going to be your product here.
00:38
This has two aldehydes.
00:42
Now our next one is similar.
00:45
We still have our six carbons.
00:53
But now on carbon one, we also have a methyl group.
00:57
So we have a ketone and an aldehyde now as our product.
01:03
Then we're asked for the retro synthesis of this...