Question

15. Write the vector below in trigonometric form. m = -10i + 10j A. m = 4?5?cos 135°, sin 135°? B. m = 4?5?cos 315°, sin 315°? C. m = 10?2?cos 135°, sin 135°? D. m = 10?2?cos 315°, sin 315°? 17. A bird is flying at a true bearing of 75° at a speed of 40 miles per hour. Write the velocity of the bird as a vector in component form. A. ?48.21, 57.45? B. ?57.45, 48.21? C. ?38.64, 10.35? D. ?10.35, 38.64?

          15. Write the vector below in trigonometric form.
m = -10i + 10j
A. m = 4?5?cos 135°, sin 135°?
B. m = 4?5?cos 315°, sin 315°?
C. m = 10?2?cos 135°, sin 135°?
D. m = 10?2?cos 315°, sin 315°?
17. A bird is flying at a true bearing of 75° at a speed of 40 miles per hour. Write the velocity of the bird as a vector in component form.
A. ?48.21, 57.45?
B. ?57.45, 48.21?
C. ?38.64, 10.35?
D. ?10.35, 38.64?

15. Write the vector below in trigonometric form.
m = -10i + 10j
A. m = 4?5?cos 135°, sin 135°?
B. m = 4?5?cos 315°, sin 315°?
C. m = 10?2?cos 135°, sin 135°?
D. m = 10?2?cos 315°, sin 315°?
17. A bird is flying at a true bearing of 75° at a speed of 40 miles per hour. Write the velocity of the bird as a vector in component form.
A. ?48.21, 57.45?
B. ?57.45, 48.21?
C. ?38.64, 10.35?
D. ?10.35, 38.64?

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University Calculus: Early Transcendentals

Joel Hass, Christopher Heil, Przemyslaw… 4th Edition

Chapter 11

Instant Answer

Solved by Expert Breanna Ollech

02/01/2024

Step 1

The magnitude of the vector m is √((-10)^2 + 10^2) = √200 = 10√2. The direction of the vector is given by the angle θ such that tan(θ) = 10/-10 = -1. This corresponds to an angle of 135° or 315°. However, since the vector points to the second quadrant (negative x Show more…

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