Question

15.00 g of aluminum sulfide (150.1 g/mol) and 10.00 g of water (18.02 g/mol) react until the limiting reactant is used up. Calculate the mass of H2S (34.08 g/mol) that can be produced from these reactants. Notice that you will need to balance the reaction equation. _Al2S3(s) + _H2O → _Al(OH)3(s) + _H2S(g) 13.89 g 10.21 g 19.67 g 9.456 g 1.108 g

Name: 1500 g of aluminum sulfide 1501 gmol and 1000 g of water 1802 gmol react until the limiting reactant is used up calculate the mass of h2s 3408 gmol that can be produced from these reactants 84653
Uploaded: 2022-08-20T15:17:14-08:00
Duration: 5 min 28 s
Channel: Adi S
Description: 1500 g of aluminum sulfide 1501 gmol and 1000 g of water 1802 gmol react until the limiting reactant is used up calculate the mass of h2s 3408 gmol that can be produced from these reactants 84653

          15.00 g of aluminum sulfide (150.1 g/mol) and 10.00 g of water (18.02 g/mol) react until the limiting reactant is used up. Calculate the mass of H2S (34.08 g/mol) that can be produced from these reactants. Notice that you will need to balance the reaction equation.

___Al2S3(s) + ___H2O → ___Al(OH)3(s) + ___H2S(g)

13.89 g
10.21 g
19.67 g
9.456 g
1.108 g

Added by Kathleen J.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

08/20/2022

Step 1

00 g Molar mass of Al2S3 = 150.1 g/mol Number of moles of Al2S3 = Mass / Molar mass Number of moles of Al2S3 = 15.00 g / 150.1 g/mol Number of moles of Al2S3 = 0.0998 mol Show more…

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15.00 g of aluminum sulfide (150.1 g/mol) and 10.00 g of water (18.02 g/mol) react until the limiting reactant is used up. Calculate the mass of H2S (34.08 g/mol) that can be produced from these reactants. Notice that you will need to balance the reaction equation. ___Al2S3(s) + ___H2O → ___Al(OH)3(s) + ___H2S(g) 13.89 g 10.21 g 19.67 g 9.456 g 1.108 g