Question

15/2411/assessments/6/121/assignment//711848 Final Exam Close Date: August 09, 2024 at 4:20 AM Question 7 of 23 11 lb of frozen cranberries were thawed, cleaned, and boiled to prepare them for a turkey dinner. They lost 1 lb 12 oz in weight during preparation. Determine the yield percent. Yield Percent \( = \) \( \square \) \% Poved tea 2 decimal places

          15/2411/assessments/6/121/assignment//711848
Final Exam
Close Date: August 09, 2024 at 4:20 AM
Question 7 of 23
11 lb of frozen cranberries were thawed, cleaned, and boiled to prepare them for a turkey dinner. They lost 1 lb 12 oz in weight during preparation. Determine the yield percent.

Yield Percent \( = \) \( \square \) \%
Poved tea 2 decimal places

15/2411/assessments/6/121/assignment//711848
Final Exam
Close Date: August 09, 2024 at 4:20 AM
Question 7 of 23
11 lb of frozen cranberries were thawed, cleaned, and boiled to prepare them for a turkey dinner. They lost 1 lb 12 oz in weight during preparation. Determine the yield percent.

Yield Percent = □ %
Poved tea 2 decimal places

Added by Anthony L.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Brittany Stefanilo

Step 1

- 1 lb 12 oz is equivalent to 1 + (12/16) lb. - 12 oz is 0.75 lb (since 12/16 = 0.75). - Therefore, 1 lb 12 oz = 1 + 0.75 = 1.75 lb. Show more…

Show all steps

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15/2411/assessments/6/121/assignment//711848 Final Exam Close Date: August 09, 2024 at 4:20 AM Question 7 of 23 11 lb of frozen cranberries were thawed, cleaned, and boiled to prepare them for a turkey dinner. They lost 1 lb 12 oz in weight during preparation. Determine the yield percent. Yield Percent \( = \) \( \square \) \% Poved tea 2 decimal places