16. (4 pts) What sample size is needed to give a margin of error of Ā±2% in estimating a population proportion with 95% confidence? We believe the population proportion is about 0.8. 17. (6 pts) Using the confidence interval given, indicate the conclusion of the test and indicate the significance level used. (a) A 95% confidence interval for a mean ? is 12.5 to 17.1. Testing H0: ? = 18 vs Ha: ? ? 18. (b) A 90% confidence interval for a proportion p is 0.62 to 0.80. Testing H0: p = 0.65 vs Ha: p ? 0.65. (c) A 99% confidence interval for a difference in proportions is - 0.10 to 0.20. Testing H0: p1 = p2 vs Ha: p1 ? p2.
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29 in estimating a population proportion with 95% confidence. We are given that the population proportion is believed to be 0.8. The formula for the margin of error (ME) is: ME = Z * sqrt(p * (1 - p) / n) where Z is the Z-score corresponding to the desired Show moreā¦
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16)You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately ? = 61.3 ? = 61.3 . You would like to be 95% confident that your estimate is within 2 of the true population mean. How large of a sample size is required? 17) You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately ? = 60.3 ? = 60.3 . You would like to be 99% confident that your estimate is within 0.1 of the true population mean. How large of a sample size is required? As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval.
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4) Construct a 95% confidence interval about the sample proportion for question 1 and determine the margin of error: Determine the following for the given information: Sample Proportion, Critical Value(s), Test Value, P-Value, Draw Diagram, State Conclusion. 5) Construct a 90% confidence interval about the sample proportion for question 2 and determine the margin of error: Construct a 99% confidence interval. Ho: p=3, M: p>3, n = 200, X = 75, a = 0.05 About the sample proportion for question 3 and determine the margin of error. 2) Ho: p = 0.55, H: p < 0.55, n = 150, X = 78, 0 =. Use binomial distribution for the small sample: Ha p = 0.62, H: p < 0.62, n = 30, X = 16, 0 = 0.05 3) Ho: p = 0.9, H: p > 0.9, n = 500, 440, a = 0.05 Calculate the P-Value, State Conclusion.
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Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for the proportion of the population in Category A given that 18% of a sample of 425 are in Category A. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point estimate = Margin of error =Ā± The 99% confidence interval is:
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