00:01
Hello student, the mean and standard deviation is given.
00:05
So here we have given x bar is equal to 42 .95 and standard deviation s is equal to 2 .6224.
00:18
So here we have to use the critical value to test the hypothesis at alpha is equal to 0 .01.
00:26
So here we set hypothesis as h naught mu is equals to 43 versus alternative hypothesis h1 mu not equal to 43.
00:37
Now test statistic for testing the given claim.
00:41
So here t is equal to x bar minus mu divided by s upon root n.
00:52
Now we substitute all the values in the given formula.
00:55
So here x bar is equal to 42 .95 minus 43 upon s is equals to 2 .6224 upon square root of 65.
01:15
Now solving it will give the value of test statistic t is equal to minus 0 .1526.
01:23
Now the critical value of tc ranges from minus 2 .6549 up to plus 2 .6549.
01:37
So here h naught cannot be rejected.
01:42
So here we fail to reject null hypothesis h naught.
01:48
Now for the next bit for the test statistic t is equal to 1 .84.
01:55
So here we have given a statistic t is equals to 1 .84...