Question

160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF The $K_a$ of hydrofluoric acid is $6.8 \times 10^{-4}$. Express your answer using two decimal places.

          160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF
The $K_a$ of hydrofluoric acid is $6.8 \times 10^{-4}$.
Express your answer using two decimal places.

160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF
The Ka of hydrofluoric acid is 6.8 × 10^-4.
Express your answer using two decimal places.

Added by Carla A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

04/02/2023

Step 1

$moles \ HF = (0.160 \ L)(0.25 \ M) = 0.040 \ mol$ $moles \ NaF = (0.230 \ L)(0.31 \ M) = 0.071 \ mol$ Show more…

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160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF The $K_a$ of hydrofluoric, acid is 6.8 x 10-4. Express your answer using two decimal places.

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160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF The $K_a$ of hydrofluoric acid is $6.8 \times 10^{-4}$. Express your answer using two decimal places.

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