00:01
So, here suppose x is reaction time in seconds of a driver and x is distributed normally at 1 .5 comma 0 .18 which implies that the g is equal to the x minus mu divided by sigma.
00:18
So, as per question we have mu and sigma.
00:20
So, we have x minus 1 .5 sigma which is 0 .18.
00:26
So, now we will solve the a part of the question.
00:28
So, here to find out the probability of x is less than 1 .35 second is equal to the it is p of g is less than.
00:39
So, here we need to put the value of x which is 1 .35 minus 1 .5 divided by 0 .18.
00:48
So, which is equal to the p of g is less than minus 0 .83.
00:54
So, by using g table we are able to get the value which is 0 .2033 which is equal to the 20 .33 percent.
01:07
So, this is the answer for the a part of the question.
01:10
So, now for the b part of the question.
01:12
So, here we need to find out the probability of x is greater than 1 .90.
01:18
So, which is equal to the p of.
01:21
So, here p of g is greater than.
01:23
So, here in the above formula we need to put x is equal to the 1 .90.
01:28
So, we have 1 .90 minus 1 .50 divided by 0 .18.
01:35
So, when we solve this out it will be p of g is greater than 2 .22.
01:43
So, by using g table we are able to get this value is equal to the 0 .0132 which is 1 .32 percent.
01:53
So, this is the answer for the b part of the question...