00:01
Hi, for this problem we will use the mawlus law, i is equal to i0 cosine squared theta, or cosine squared delta theta, where i0 is the incident beam intensity, and i is the output beam intensity.
00:20
And delta theta is the angle between the two polarizers.
00:25
So first of all, after the first polarizer, half of the intensity is gone, so i1, let's call it, would be equal to intensity of the beam, initial intensity of the beam, half.
00:39
That would be 1260 watt per meter squared over half, gives us 630 watt per meter squared.
00:47
Now this is the beam that is falling on the second polarizer, so that would be its intensity, called i0 in this case...