Question

17. A coil with an impedance of $30\angle53.13^\circ \Omega$ is connected across a 50-Hz ac source. The Fourier equation of the voltage measured with an oscilloscope is: $\qquad e(t) = 25 + 311 \sin \left(\omega t + \frac{\pi}{12}\right) + 196 \sin \left(2\omega t + \frac{\pi}{9}\right) + 164 \sin \left(4\omega t + \frac{\pi}{6}\right) +$ $\qquad 125 \sin \left(6\omega t + \frac{\pi}{4}\right) V$ The circuit is set to resonate at the fourth harmonic for maximum active power output. Calculate this power. (791.224 W)

          17.
A coil with an impedance of $30\angle53.13^\circ \Omega$ is connected across a 50-Hz ac source. The
Fourier equation of the voltage measured with an oscilloscope is:
$\qquad e(t) = 25 + 311 \sin \left(\omega t + \frac{\pi}{12}\right) + 196 \sin \left(2\omega t + \frac{\pi}{9}\right) + 164 \sin \left(4\omega t + \frac{\pi}{6}\right) +$
$\qquad 125 \sin \left(6\omega t + \frac{\pi}{4}\right) V$
The circuit is set to resonate at the fourth harmonic for maximum active power output.
Calculate this power.
(791.224 W)

17.
A coil with an impedance of 30∠53.13^∘Ω is connected across a 50-Hz ac source. The
Fourier equation of the voltage measured with an oscilloscope is:
e(t) = 25 + 311 sin(ω t + (π)/(12)) + 196 sin(2ω t + (π)/(9)) + 164 sin(4ω t + (π)/(6)) +
125 sin(6ω t + (π)/(4)) V
The circuit is set to resonate at the fourth harmonic for maximum active power output.
Calculate this power.
(791.224 W)

Added by Travis S.

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