00:01
As per the question, this is ball number 1.
00:04
Ball number 1 at point a.
00:08
Now it is inclined towards surface which looks something like this.
00:14
Now this is the inclined surface.
00:17
This is point number b.
00:19
Here is another ball, that is ball number 2.
00:23
Now this ball number 1 is made to go upwards and this ball number 2 is coming downwards.
00:30
Now let us assume that they meet at a point c.
00:33
Let us assume this to be point c.
00:35
Now take the distance of a to b as h while from c.
00:43
Take ac distance, let us assume ac distance to be x while bc distance to be y.
00:51
Now they are colliding at this point.
00:54
Collision happens.
00:55
Collide.
00:57
Right? we need to find the ratio r which is equal to ac, the value for magnitude of ac divided by the magnitude for bc.
01:09
Now to find this, we are given that u, what will be u? u should be the minimum velocity to reach the height h.
01:22
To reach height h.
01:24
This minimum velocity would be with ball number 1.
01:28
For ball number 1.
01:30
So the value of u must be equal to under root 2 into acceleration into height.
01:38
Now similarly we can have the value for acceleration is equal to g sine theta.
01:46
Now let us take this angle to be theta, the angle of inclination.
01:50
So theta here is angle of inclination.
01:58
Now we are given with the acceleration.
02:02
Now we have the u.
02:04
Let us suppose that they met after time t.
02:11
After time interval is t.
02:15
Who are they? these are the two balls.
02:17
Two balls are colliding after time t.
02:19
So then we can say ac will be equal to x as we have assumed it.
02:25
Ac is equal to x.
02:28
So x will be equal to, now according to the equation of motions, ut minus half at square...