17 points: A BJT with β = 95 and Vbe = 110V is biased such that the quiescent base current is 23.2μA. The transistor's temperature is 300 K. Determine gm and rm.
Added by Silvia B.
Close
Step 1
We know that the quiescent base current (Ib) is 23.2μA. Since β = Ic/Ib, we can rearrange this equation to solve for Ic. Ic = β * Ib Ic = 95 * 23.2μA Ic = 2.204mA Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 69 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
5.4 The pnp transistor in the circuit shown has β = 50. Assuming that the BJT is operating in the saturation mode (VCEsat = 0.2 V), find β_forced and Vc.
Adi S.
A Si p-n-p BJT has the following parameters at room temperature. Emitter Base Na = 10^16 Tp = 2500 ps n = 1500 p = 400 Collector Na = 10^15 Tn = 2 us Pn = 1500 pp = 450 Na = 5 x 10^18 cm^-3 Tn = 100 ps n = 150 cm^2/V-s p = 100 cm^2/V-s Base width W = 0.2 m Area = 10^-4 cm^2 Calculate the β of the transistor from B and γ, and using the charge control model. Comment on the results.
Sri K.
(II) Suppose that the current gain of the transistor in Fig. 43 is $\beta=i_{C} / i_{B}=85 .$ If $R_{C}=4.3 \mathrm{k} \Omega$ , calculate the ac output voltage for an ac input current of 2.0$\mu \mathrm{A} .$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD