Question

18. (2 pts ea) Circle T for true or F for false. (a) T F \frac{\log_b(A)}{\log_b(B)} = \log_b(A) - \log_b(B). (b) T F \frac{1}{a} + \frac{1}{b} = \frac{a+b}{ab} (c) T F f(a+b) = f(a) + f(b) for any function $f$ and real numbers $a$ and $b$. (d) T F $(a+b)^2 = a^2 + b^2$ (e) T F If $f(-x) = -f(x)$, for all $x \in$ Domain $f$, then $f$ is an odd function. (f) T F $b^{\log_b x} = x$. (g) T F The graph of an odd function is symmetric with respect to the origin. (h) T F Ordered pairs on the graph of $y = f(x)$ have the form $(x, f(x))$. (i) T F $y = \log_b(x)$ is equivalent to $b^y = x$. (j) T F The domain of $y = \log_b(x)$ is $(-\infty, \infty)$.

          18. (2 pts ea) Circle T for true or F for false.
(a) T F \frac{\log_b(A)}{\log_b(B)} = \log_b(A) - \log_b(B).
(b) T F \frac{1}{a} + \frac{1}{b} = \frac{a+b}{ab}
(c) T F f(a+b) = f(a) + f(b) for any function $f$ and real numbers $a$ and $b$.
(d) T F $(a+b)^2 = a^2 + b^2$
(e) T F If $f(-x) = -f(x)$, for all $x \in$ Domain $f$, then $f$ is an odd function.
(f) T F $b^{\log_b x} = x$.
(g) T F The graph of an odd function is symmetric with respect to the origin.
(h) T F Ordered pairs on the graph of $y = f(x)$ have the form $(x, f(x))$.
(i) T F $y = \log_b(x)$ is equivalent to $b^y = x$.
(j) T F The domain of $y = \log_b(x)$ is $(-\infty, \infty)$.

18. (2 pts ea) Circle T for true or F for false.
(a) T F ((A))/((B)) = (A) - (B).
(b) T F (1)/(a) + (1)/(b) = (a+b)/(ab)
(c) T F f(a+b) = f(a) + f(b) for any function f and real numbers a and b.
(d) T F (a+b)^2 = a^2 + b^2
(e) T F If f(-x) = -f(x), for all x ∈ Domain f, then f is an odd function.
(f) T F b^ x = x.
(g) T F The graph of an odd function is symmetric with respect to the origin.
(h) T F Ordered pairs on the graph of y = f(x) have the form (x, f(x)).
(i) T F y = (x) is equivalent to b^y = x.
(j) T F The domain of y = (x) is (-∞, ∞).

Added by Debra O.

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