19. An instructor gives a test before and after a tutoring session and results from randomly selected students are given here. Test the claim that the tutoring improved scores. Before 64 51 67 87 51 67 34 71 81 After 70 56 64 89 51 77 42 71 90 a. Find the P-value b. Will the null hypothesis be rejected? Use alpha = 0.05. 20. Here is data on student absences by day of the week. Conduct a test of the claim that students miss days of the week with equal frequency. Mon Tues Wed Thurs Fri 23 17 28 21 31 a. What is the P-value? b. Will the null hypothesis be rejected? Use $\alpha$ = 0.10 a) P = 0.010 b) P = 0.0237 c) P = 0.0271 d) P = 0.0135 e) None of the above a) Yes b) No c) It depends d) Not enough information e) None of the above a) P = 0.0325 b) P = 0.0321 c) P = 0.352 d) P = 0.271 e) None of the above a) Yes b) No c) It depends d) Not enough information e) None of the above
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The null hypothesis is that there is no difference in scores before and after tutoring, while the alternative hypothesis is that the scores improved after tutoring. Show more…
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A random sample of 10 college students was drawn from a large university. Their ages are 22, 17, 27, 20, 23, 19, 24, 18, 19, and 24 years. We want to determine if we can infer at the 5% significance level that the population mean is not equal to 20. Answer the following four questions: a) What are the null and alternative hypotheses to run this test? a. H0: X̄ = 20 ; H1: X̄ ≠20 d. H0: μ = 20 ; H1: μ ≠20 b. H0: μ = 20 ; H1: μ > 20 e. none of the above c. H0: μ ≠20 ; H1: μ = 20 b) What is the calculated value of the test statistic needed to test the hypothesis in 2a? a. -1.355 b. 1.355 c. 1.285 d. 4.064 e. none of the above c) What is the p-value of the calculated test statistic? a. 0.231 b. 0.099 c. 0.199 d. 0.115 e. none of the above d) Which of the following best describes your conclusion? a. Do not reject the null hypothesis since p-value < α. Population mean is equal to 20. b. Reject the alternative hypothesis since p-value > α. Population mean is not equal to 20. c. Do not reject the null hypothesis since p-value > α. Average age of all students is equal to 20. d. Reject the null hypothesis since p-value > α. Average age of all students is not equal to 20. e. none of the above
Adi S.
a) State the null hypothesis H0 and the alternative hypothesis H1 that you would use for the test. b) For your hypothesis test, you will use a Z-test. Find the values of np and n(1-p) to confirm that a Z-test can be used. (One standard is that np is greater than or equal to 10 and n(1-p) is greater than or equal to 10 under the assumption that the null hypothesis is true.) Here n is the sample size and p is the population proportion you are testing. c) Perform a Z-test and find the p-value. One-tailed or two-tailed? What is the test statistic? What is the p-value? d) Based on your answer to part (c), choose what can be concluded, at the 0.05 level of significance, about the claim made in the school's reports. 1. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 43% of students will find a match their first time using the site. 2. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 43% of students will find a match their first time using the site. 3. Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 43% of students will find a match their first time using the site. 4. Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 43% of students will find a match their first time using the site.
Daniel C.
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