00:01
F of x equals x minus 2 over x plus 1 squared.
00:09
And i'm asked to find the asymptotes and the domain and range.
00:19
Okay, this function is going to have a vertical asymptote where the denominator would be 0.
00:35
So that's going to be at x equals negative 1.
00:43
It's going to have a horizontal asymptote at the x -axis, and that's because the degree of the numerator is less than the degree of the denominator.
00:59
I'm sketching the graph, i know that it's going to cross the x -axis at 2, which may sound odd because it has this asymptope at zero, but you can cross a horizontal asymptote.
01:18
The y intercept, if i put in zero for x, i'm going to get negative 2 over 1, so a y intercept of 2.
01:29
And this tells me my graph is going to kind of go like this.
01:33
And then it's going to cross and it's going to hover right along the x -axis just barely above it...