00:01
We're given the molecular formula and c2, h3, vr.
00:09
So first we're going to look for degrees of unsaturation.
00:12
So this tells us the combined number of rings and pi bonds.
00:18
So we multiply the number of carbons by two and add two.
00:22
Then we subtract the number of hydrogens and halogens, so that's bromine, and divide by two.
00:28
So here we have six minus four or two.
00:32
So we get one.
00:32
So we're going to have one double bond, and bromine is a halogen.
00:38
It likes to have single bonds as two hydrogens.
00:41
So our double bond must be between our carbons, and that leaves two bonds left on each side.
00:50
So in one of these, we're going to have two hydrogens...