00:01
Here given that a viscous oil flow is tidily between straight parallel planes and the flow is assumed to be laminar and fully developed given.
00:08
Given del p divided where del x is equals to minus thousand thousand newton per meter square per meter and the value of gap is given as 5 m m and dynamic viscosity is 0 .5 0 .5 newton second per meter square.
00:30
Now as we know, as we know, velocity profile for a pressure driven lemnarder flow between stationary parallel plate, it can be written as uy, uy is equals to minus h by 2 divided by h is whole square divided by 2 mu, multiplied by 2m, multiplied by del p divided del x multiplied by 1 minus y divided by h by 2 whole square this is this is velocity at half the channel width at a is equal to h divided at 2 or we get the velocity profile u y is equal to minus h squared divided by 8 mu del p divided del x multiplied by 1 minus 2 y divided by h whole square let this equation be equation number 2 and this equation be question now we will calculate the cer stress now cr stress c.
02:03
Ttou is equal to mu multiplied by du divided by d.
02:09
So we will write it as mu multiplied by mu the value of u is minus h squared divided by 8 mu del p divided del x multiplied by 1 minus 2 y divided by h whole square so this will be equals to here mu mu will cancel out its so it will be equal to minus h squared divided by 8, multiplied by del p divided by del f multiplied by the differentiation of this term with respect to y will be will be 8, 8 y divided by h square.
03:00
From here we get tau is equal to y multiplied by minus this term will be minus y multiplied by del p divided del x this equation get this equation number three we will put the values and we will get the answer so let's put the value of y is as h by 2 where the value of h is given as 5 multiplied by 10 to the power of 3 divided 2 multiplied by del p.
03:33
Divided del x is given as minus 1000.
03:37
So it will come out to be minus 2 .5 newton per meter square...