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1a1-Counting Your Material Aluminum Oxide ($Al_2O_3$) 3 lb = 1359 g Atomic mass of each element in your material Al 26.98g/mol O 16g/mol O 16g/mol # of molecules in 3 lb 1.352e12 # of atoms of each element in 3 lb Al 1.352e12 O 2.705e12 O 2.705e12 # of total protons in 3 lb 6.386e12 # of total electrons in 3 lb 6.386e12 * protons and electrons are equal because $Al_2O_3$ is neutral # of total neutrons in 3 lb 6.598e12 WORKSPACE Al 26.98 g/mol $Al_2O_3$ 26.98 g/mol + 16g/mol + 16g/mol = 58.98 g/mol 1359 g 58.98 g/mol = 23.042 moles $Al_2O_3$ # of molecules = 23.042 mol $\cdot$ 6.023e23 molecules/mol = 1.352e12 molecules # of atoms Al = 1.352e12 atoms Al # of atoms O = 2(1.352e12 atoms) = 2.705e12 atoms O # of protons = 13(1.352e12 Al) + 8(2.705e12 O) = 6.383e12 # of neutrons = Al = 26.98 - 13 = 13.98 O = 16 - 8 = 8 $Al_2O_3$ 13.98(1.352e12 atoms Al) + 8(2.705e12 atoms O) = 6.598e12 1a2 Density and Volume Your Material $Al_2O_3$ 8 oz = 236.8 cm³ Density of your Material 3.99 g/cm³ Mass of 8 oz of your material 944.89 g Number of Molecules in 8 oz of your material 940.2e9 Number of Atoms of each element in 8 oz Al 940.2e9 O 15.24e6 O 15.24e6 WORKSPACE 8 oz = 8 oz $\cdot$ 29.6cm³/102 = 236.8cm³ Volume = mass/density $M_{Al_2O_3}$ = $\rho \cdot V$ = 3.99g/cm³ $\cdot$ 236.8cm³ = 944.8g #moles = 944.8g / 58.98 g/mol = 16.02 moles # molecules = 16.02 moles $\cdot$ 6.023e23 molec/mol = 940.2e9 molecules # atoms Al = 940.2e9 atoms Al # atoms O = 2(940.2e9) = 15.24e6

          1a1-Counting
Your Material Aluminum Oxide ($Al_2O_3$) 3 lb = 1359 g
Atomic mass of each element in your material Al 26.98g/mol O 16g/mol O 16g/mol
# of molecules in 3 lb 1.352e12
# of atoms of each element in 3 lb Al 1.352e12 O 2.705e12 O 2.705e12
# of total protons in 3 lb 6.386e12
# of total electrons in 3 lb 6.386e12 * protons and electrons are equal because
$Al_2O_3$ is neutral
# of total neutrons in 3 lb 6.598e12
WORKSPACE
Al 26.98 g/mol
$Al_2O_3$ 26.98 g/mol + 16g/mol + 16g/mol = 58.98 g/mol
1359 g
58.98 g/mol = 23.042 moles $Al_2O_3$
# of molecules = 23.042 mol $\cdot$ 6.023e23 molecules/mol = 1.352e12 molecules
# of atoms Al = 1.352e12 atoms Al
# of atoms O = 2(1.352e12 atoms) = 2.705e12 atoms O
# of protons = 13(1.352e12 Al) + 8(2.705e12 O) = 6.383e12
# of neutrons = Al = 26.98 - 13 = 13.98
O = 16 - 8 = 8
$Al_2O_3$ 13.98(1.352e12 atoms Al) + 8(2.705e12 atoms O) = 6.598e12
1a2 Density and Volume
Your Material $Al_2O_3$
8 oz = 236.8 cm³ Density of your Material 3.99 g/cm³
Mass of 8 oz of your material 944.89 g
Number of Molecules in 8 oz of your material 940.2e9
Number of Atoms of each element in 8 oz Al 940.2e9 O 15.24e6 O 15.24e6
WORKSPACE
8 oz = 8 oz $\cdot$ 29.6cm³/102 = 236.8cm³ Volume = mass/density
$M_{Al_2O_3}$ = $\rho \cdot V$ = 3.99g/cm³ $\cdot$ 236.8cm³ = 944.8g
#moles = 944.8g / 58.98 g/mol = 16.02 moles
# molecules = 16.02 moles $\cdot$ 6.023e23 molec/mol = 940.2e9 molecules
# atoms Al = 940.2e9 atoms Al
# atoms O = 2(940.2e9) = 15.24e6

1a1 counting your material aluminum oxide al2o3 3 lb 1359 g atomic mass of each element in your material al 2698gmol o 16gmol o 16gmol of molecules in 3 lb 1352e12 of atoms of each element 19307

Added by Anita M.

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