Question

1.An aluminum wire 10 m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is $3.8 \times 10^7 \text{ (?-m)}^{-1}$, calculate the minimum diameter of the wire.

Name: 1.An aluminum wire 10 m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is 3.8 × 10^7 (?-m)^-1, calculate the minimum diameter of the wire.
Uploaded: 2021-10-30T12:16:28-08:00
Duration: 1 min 11 s
Channel: Narayan Hari
Description: 1.An aluminum wire 10 m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is 3.8 × 10^7 (?-m)^-1, calculate the minimum diameter of the wire.

          1.An aluminum wire 10 m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is $3.8 \times 10^7 \text{ (?-m)}^{-1}$, calculate the minimum diameter of the wire.

1.An aluminum wire 10 m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is 3.8 × 10^7 (?-m)^-1, calculate the minimum diameter of the wire.

Added by Brad D.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Narayan Hari

10/30/2021

Step 1

Step 1: We can use the formula for voltage drop, which is V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Show more…

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1.An aluminum wire 10m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is 3.8 imes 10^(7)(Omega -m)^(-1), calculate the minimum diameter of the wire. 1.An aluminum wire 10 m long must experience a voltage drop of less than 1V when a current of 5A passes through it. Given the conductivity of aluminum at room temperature is 3.8 107 (-m)-', calculate the minimum diameter of the wire.