00:01
And this question, you have three subquassum first is about electron.
00:05
So the electron is traveling at the speed, which is v equals 0 .2, that of speed of lighting vacuum, c, right? and then what is the energy of the electron? that is given by, the current energy is given by m, c squared over square root of 1 minus v squared over c squared, right? so that is given by, according to the question, so the question mc squared is given by 0 .511 m mega -electroats over 1 minus 0 .04, right? so that is roughly about 0 .45.
00:45
M .e .v, i guess it's about 1 plus 0 .02, right? so that's the total energy of the electron.
01:00
And the momentum of the electron is given by m, which is speed divided by our course, but same factor, c squared.
01:11
And that is given by, we can rewrite this as, you know, we can write it as mc squared, v over c squared, and then times roughly, we can evaluate this factor in a similar way, so roughly about 1 .002 and that'll be it.
01:29
So mc squared according to question is 511 omega electric 4, right? and we oversee, according to question, it's just given by point two.
01:41
So over c, right, point two over c, that's a result...