00:01
Hello everyone, let's start the question.
00:03
In this question we're talking about a solution for which we are given with the value of hydrogen ion, the concentration of hydrogen ion as 2 .70 multiplied by 10 raised to the power negative 6 molars.
00:21
We are asked to calculate the value of ph and poh which is associated with this particular concentration that is molarity.
00:33
So first if we calculate the ph, we know that as ph is equal to negative logarithm of the concentration of hydronium ions.
00:45
If we substitute the values here, ph will be equal to negative log of 2 .70 multiplied by 10 raised to the path, negative if we simplify this further, we will obtain the value of ph in this case as 5 .5687.
01:11
This is the value for ph.
01:13
Now we have got the value of ph.
01:15
We can easily calculate ph by using the relation.
01:21
The sum of ph and p .o .h is equal to 14.
01:25
Let us number this particular relation as 1 and from the relation...