Based on a sample of 65 people, the sample mean GPA was 2.24 with a standard deviation of 0.03. The p-value is: (to 2 decimals).
Added by Victor B.
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24\), \(\mu = 2.27\), \(\sigma = 0.03\), and \(n = 65\), we have: \( z = \frac{2.24 - 2.27}{\frac{0.03}{\sqrt{65}}} = -2.90 \) Show more…
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