1- Consider the circuit shown below. Solve the circuit by Laplace transforms and obtain $I_L(t)$.\\ R1\\ 6\\ i\\ V1\\ 12V\\ L1\\ 1H\\ a) 2u(t) - 2.4e^{-5t}\\ b) 2.4u(t) - 2.4e^{-5t}\\ c) 2u(t) - 2e^{-5t}\\ d) 2.4u(t) - 2.4e^{-5t}\\ e) 2u(t) + 2.4e^{-5t}\\ f) none of these
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The Laplace transform of a constant voltage is simply the constant itself. So, the Laplace transform of V1(t) is V1(s) = 12V. Show more…
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