1D. A 1000N block A is suspended from a rope that runs around the fixed pegs B and C. The coefficient of friction between the pegs and the rope is µs = 0.25. Determine the total angle of wrap for both pegs and the minimum force P needed to hold the block in static equalibrium. $\beta_{Tot}$ = $P_{Min}$ = P C 40° B A 1000N (3 pts) (2 pts)
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For peg B, the angle of wrap is 180 degrees or $\pi$ radians. For peg C, the angle of wrap is also 180 degrees or $\pi$ radians. Show more…
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1C) A 100-lb block A is lowered using a rope and two fixed pegs B and C. If the static coefficient of friction between the rope and pegs is μs = 0.3, determine the total angle of wrap (βTot = βB + βC) and the minimum force (Pmin) to barely hold the block in equilibrium. (5 pts) βTot = degrees (3 pts) Pmin = lbs (2pts)
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