00:01
Dear students, question is determine the amount of magnesium needed to obtain 2 millimole and amount of bromobengen needed to obtain 2 .1 millimole of phenyl magnesium bromide.
00:11
So there are two questions here.
00:14
One, let us write the equation.
00:17
Magnesium plus bromogen, c6h5 br.
00:28
So it will be c6h5 mgbr, that is phenyl magnesium bromide.
00:34
Now, as per the balanced equation, one mole of magnesium reacts with one more of phenyl bromide to give one mole of a phenyl magnesium bromide.
00:44
Therefore, here it is saying what is the amount of magnesium needed to obtain 2 millimole of feral magnesium bromide.
00:56
So first let us calculate the amount of magnesium required.
01:02
Now here, 1 mole of magnesium required to get 1 mole of phenyl magnesium bromide.
01:06
So, for 1 mole of phenyl magnesium bromide, we need magnesium 1 mole.
01:20
Now question is for 2 millimoles.
01:23
Therefore 2, for 2 millimoles of phenyl magnesium bromide, we need 2 millimole magnesium, which is equal to in gram, it is 2 multiplied by 10 to minus 3 mole, which is equal to 2 multiplied by 10...