Explain the cause and origin of the high reverse bias current after breakdown of a PN junction.
Added by Jordan S.
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This depletion region acts as a barrier to the flow of current. However, if the reverse bias voltage is increased beyond a certain threshold value, the electric field across the depletion region becomes strong enough to ionize the atoms in the crystal lattice, Show more…
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Explain the cause and origin of the high reverse bias current after breakdown of a PN junction
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1) (a) In PN junction, why is the reverse-bias current expected to be small in magnitude and to saturate at small reverse voltage? (b) In PN junction, under revise biasing, what processes occur in the quasineutral regions adjacent to the depletion region edges? It is drift and diffusion, diffusion and recombination, generation and diffusion, or generation and drift? (c) In BJT, define in words (no equations) what is meant by ‐emitter efficiency‐. (d) In the ideal transistor analysis, what assumptions are made about the regional (E B C) doping concentrations and quasineutral widths? (e) What are the differences between a BJT and HBT? (f) In a p+-n junction, the n-doping Nd is doubled. How do the following change if everything else remains unchanged? Indicate only increase or decrease. (f1) Junction capacitance (f2) Built-in potential (f3) Breakdown voltage (f4) Ohmic losses (g) An idea MS contact is formed between a metal and a semiconductor with ΦM =χ. Under what conditions will the contact be ohmic-like, and under what conditions will the contact be rectifying?
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