(1+i)^8
Added by Amit D.
Step 1
First, we can expand (1+i)^2 as follows: (1+i)^2 = 1 + 2i + i^2 Since i^2 = -1, we can simplify this to: (1+i)^2 = 1 + 2i - 1 = 2i Show more…
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