Question

In a Young's double slit experiment, the separation of the slits is 0.26 mm. The wavelength of the light is 549 nm. Determine the angle at which the third dark fringe occurs from the center. Give your answer as a positive value.

Name: 1in a youngs double slit experiment the separation of the slits is 026 mm the wavelength of the light is 549 nm determine the angle at which the third dark fringe out from the centre occurs 19006
Uploaded: 2022-03-21T13:20:31-08:00
Duration: 1 min 25 s
Channel: Prabhu Ramji
Description: 1in a youngs double slit experiment the separation of the slits is 026 mm the wavelength of the light is 549 nm determine the angle at which the third dark fringe out from the centre occurs 19006

          In a Young's double slit experiment, the separation of the slits is 0.26 mm. The wavelength of the light is 549 nm. Determine the angle at which the third dark fringe occurs from the center. Give your answer as a positive value.

Added by Vicenta A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

03/21/2022

Step 1

For the dark fringe in a Young's double slit experiment, the condition is given by: $$ d \sin \theta = (m + \frac{1}{2}) \lambda $$ where $d$ is the separation of the slits, $\theta$ is the angle at which the dark fringe occurs, $m$ is the order of the fringe, Show more…

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In a Young's double slit experiment, the separation of the slits is 0.26 mm. The wavelength of the light is 549 nm. Determine the angle at which the third dark fringe occurs from the center. Give your answer as a positive value.