00:01
In this question, we have to calculate the mid band again for that the data given is ie is 1 milliampere and beta is 200.
00:12
Now we can calculate ic.
00:14
Ic will be beta by 1 plus beta into ie which is 180 ampere.
00:21
Now in calculating this, this will be 0 .995 milliampere.
00:27
And after that we get gm.
00:30
Gm is ic by voltage.
00:35
This will be 8 by 201.
00:37
Now this is the transconductance and from here we can calculate this.
00:43
That was the transconductance.
00:45
From here we get the resistance.
00:46
This will be the ratio of beta by transconductance.
00:51
This will be 5025 ohm.
00:55
This is the resistance.
00:56
And r0 will be va by ic.
01:01
This will be 50 .25 kilo ohm.
01:05
And since we have calculated this and we know that v0 is equal to minus of beta ie.
01:15
This is basically 6k, 4050 .25k...