The double-slit experiment exhibits interference peaks which have a varying intensity due to their sitting under a broader envelope of diffraction peaks. What is the correct explanation for this phenomenon?
a. The width of the slits determines the diffraction pattern, and the separation distance between the slits determines the interference pattern.
b. The width of the slits determines the interference pattern, and the separation distance between the slits determines the diffraction pattern.
c. One of the slits causes the interference pattern, and the other slit causes the diffraction pattern.
d. Each pair of wavefronts interferes at two points, causing the two patterns.
2. In the double-slit experiment, if the distance between the two slits is increased, how will the number of interference peaks under each peak of the diffraction envelope change?
a. There will be no change
b. There will be more peaks
c. There will be fewer peaks
3. We used a red laser with a wavelength of 650 nm. If we instead used a blue helium-cadmium laser with a wavelength of 442 nm, would the interference pattern be compressed (peaks narrower and more closely spaced) or expanded (peaks wider and less closely spaced)?
a. Expanded
b. Compressed
c. No difference
4. In the double-slit experiment, doubling the distance between the slits will have what effect?
a. The fringe spacing will be doubled
b. The fringe spacing will be halved
c. The wavelength will be halved
d. The wavelength will be doubled
5. Light with a wavelength of 600 nm passes through a single slit with a width of 10 μm, and a screen is placed 1 m from the slit. What is the distance between the center maximum and the third minimum? Answer in cm.