1. What must be invested today to be worth $20,000 in 10 years if it is compounded yearly at 8%? 2. Show as a sum or difference of simple (single symbol argument) logs: Log[(AB)/(CD)] 3. The half-life of carbon 14 is 5730 years. How old is a bone containing 20% of its original carbon 14?
Added by Joshua R.
Step 1
To find the present value (PV) that must be invested today, we can use the formula for compound interest: PV = FV / (1 + r)^n where FV is the future value, r is the annual interest rate, and n is the number of years. Plugging in the given values, we get: PV = Show more…
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a) Carbon-14 has a half-life of 5730 yr. Write a model of the form A(t) = A0e^-kt to represent the amount A(t) of carbon-14 remaining after t years. b) An archeologist uncovers human remains at an ancient Roman burial site and finds that 76.6% of the carbon-14 still remains in the bone. How old is the bone? Round to the nearest hundred years
James K.
1. The half-life of carbon-14 is approximately 5730 years. If we have 100 g of carbon-14 today, how much is left in 50 years? 2. If an artifact that originally contained 100 g of carbon now contains 10 g of carbon, how old is it?
Shaiju T.
The half-life for Carbon-14 is 5,730 years. How old is a bone if it presently contains 0.3125 g of Carbon-14, but it was estimated to have originally contained 80 g of Carbon-14? (hint: it went from 80 g to 0.3125 g, how many half-lives is that? Now calculate the years)
Adi S.
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