00:01
So, in this question it is given that the frequency is 9 .4 ghz.
00:12
So, the value of lambda which is equals to c divided by f is equals to 3 multiplied with 10 to the power 8 divided by 9 .4 multiplied with 10 to the power 9.
00:27
So, this is equals to 0 .032.
00:30
G which is known as antenna gain, its value is given as 32 db which is equals to 1584 .89 and the target rcs which is equals to 0 db sm, its value on conversion is 0 .001.
01:04
So, to solve this question we can apply the formula for range which is given by r.
01:19
So, r to the power 4 is equals to pt multiplied with g square multiplied with lambda square multiplied with 6 divided by 4 pi cube multiplied with p minimum.
01:41
So, here p minimum is the minimum power of receiver which is given.
01:56
So, upon substituting the values we get p minimum equals to pt multiplied with g square multiplied with lambda square multiplied with 6 divided by 4 pi cube multiplied with r to the power 4.
02:20
This is equals to 100 multiplied with 1584 .89 square multiplied with 0 .032 square multiplied with 0 .001 whole divided by 4 pi cube multiplied with 50 to the power 4...