2.) 25.0 L of an ideal gas at 278 K and 4.11 atm are heated to 393 K with a new pressure of 7.00 atm. What is the new volume (in L)?
Added by Mary R.
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However, since the amount of gas and the gas constant remain the same, we can simplify this to P1V1/T1 = P2V2/T2. We are given: P1 = 4.11 atm V1 = 25.0 L T1 = 278 K P2 = 7.00 atm T2 = 393 K We need to find V2. So, we rearrange the equation to solve for V2: Show more…
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