00:01
My approach to integrating this problem, you don't have to do it my way, but i like to use u substitution to explain it, is to just let u equal this x plus 1.
00:15
And so then du is going to equal this piece over here.
00:19
The derivative of u is du.
00:22
The derivative of x is dx.
00:24
The derivative of 1 is 0.
00:26
So what i can do is i can rewrite this problem now.
00:29
Using that u substitution, i can replace that x plus 1 with u.
00:36
And i'm actually going to rewrite this 2 thirds as the negative 2 thirds power, because it's in the denominator.
00:43
And that dx is equal to du.
00:46
Now there's one more thing we have to change, and that is these negative 2's.
00:52
That negative 2 is for x.
00:54
We have to change it so it's in terms of u.
00:56
Well, negative 2 plus 1 is negative 1...