Question

Consider the expansion of (2x^4 + x^2/k)^12, k != 0. The coefficient of the term in x^40 is five times the coefficient of the term in x^38. Find k.

Name: Consider the expansion of (2x^4 + x^2/k)^12, k != 0. The coefficient of the term in x^40 is five times the coefficient of the term in x^38. Find k.
Uploaded: 2023-02-07T04:26:10-08:00
Duration: 5 min 26 s
Channel: Supreeta N
Description: Consider the expansion of (2x^4 + x^2/k)^12, k != 0. The coefficient of the term in x^40 is five times the coefficient of the term in x^38. Find k.

          Consider the expansion of (2x^4 + x^2/k)^12, k != 0. The coefficient of the term in x^40 is five times the coefficient of the term in x^38. Find k.

Added by Darren T.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Supreeta N

02/07/2023

Step 1

The general term in the expansion is given by: \[ T_r = \binom{12}{r} (2x^4)^{12-r} \left(\frac{x^2}{k}\right)^r \] Show more…

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2. Consider the expansion of (2x^4 + x^2/k)^12, k != 0. The coefficient of the term in x^40 is five times the coefficient of the term in x^38. Find k.