Question

2. A 0.2600 g sample of an unknown acid required 28.22 mL of 0.1199 M NaOH for neutralization to a phenolphthalein end point. a. How many moles of OH- are used? (Answer in moles) b. How many moles of H+ are found in the acid? (Answer in moles) c. What is the calculated equivalent molar mass of the unknown acid? (Answer in g mol-1)

Name: 2 a 02600 g sample of an unknown acid required 2822 ml of 01199 m naoh for neutralization to a phenolphthalein end point a how many moles of oh are used answer in moles b how many moles of h 89763
Uploaded: 2023-03-25T05:52:19-08:00
Duration: 2 min 39 s
Channel: Sri K
Description: 2 a 02600 g sample of an unknown acid required 2822 ml of 01199 m naoh for neutralization to a phenolphthalein end point a how many moles of oh are used answer in moles b how many moles of h 89763

          2. A 0.2600 g sample of an unknown acid required 28.22 mL of
0.1199 M NaOH for neutralization to a phenolphthalein end
point. 
a. How many moles of OH- are used? (Answer in moles)
b. How many moles of H+ are found in the acid? (Answer
in moles)
c. What is the calculated equivalent molar mass of the unknown
acid? (Answer in g mol-1)

Added by Ernest B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

03/25/2023

Step 1

02822 L × 0.1199 mol/L moles of OH- = 0.003381 mol b. Since the acid and NaOH react in a 1:1 ratio, the moles of H+ in the acid are equal to the moles of OH- used. moles of H+ = moles of OH- = 0.003381 mol c. Show more…

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2. A 0.2600 g sample of an unknown acid required 28.22 mL of 0.1199 M NaOH for neutralization to a phenolphthalein end point. a. How many moles of OH- are used? (Answer in moles) b. How many moles of H+ are found in the acid? (Answer in moles) c. What is the calculated equivalent molar mass of the unknown acid? (Answer in g mol-1)