00:01
Hello students, in this problem we want to find the stiffness.
00:04
It is given that grip equal to 2 into 3 plus 0 .095 which is equal to 6 .19 inch.
00:20
Now length of bolt l less than or equal to 6 .19 inch plus 7 by 16 inch which is equal to 6 .628 inch.
00:38
Now rounding up l equal to 6 .75 inch.
00:46
Now lt equal to 2d plus 1 by 4 which is equal to 2 into 0 .5 plus 0 .25 which is equal to 1 .25 inch.
00:59
And id equal to l minus lt which is equal to 6 .75 minus 1 .25 which is equal to 5 .5 inch.
01:14
Then it equal to i minus id which is equal to 6 .19 minus 5 .5 which is equal to 0 .69 inch.
01:26
Now area ad equal to 5 into 0 .5 whole square divided by 4 which is equal to 0 .1963 inch square.
01:40
Now from table 8 -2, at equal to 0 .1419 inch square.
01:53
Now stiffness kb equal to ad into at into e divided by ad into it plus at into id.
02:04
That is equal to 0 .1963 into 0 .1419 into 30 divided by 0 .1963 into 0 .69 plus 0 .1419 into 5 .5.
02:26
That is stiffness kb equal to 0 .9124 mlbf by inch...