2. A 40-kg cylinder pulley with a radius of 0.2 m rotates at a constant angular speed of 4 rad/s. What is the rotational kinetic energy of the pulley? The moment of inertia for cylinder is given as I=1/2 mr2.
Added by Anne G.
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Here, m is the mass of the pulley (40 kg) and r is the radius of the pulley (0.2 m). I = 1/2 * 40 kg * (0.2 m)^2 = 0.8 kg*m^2 Show more…
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