00:01
We have a circuit like this having c1 is equal to 3 muf, c2 is equal to 9 muf, and c3 is equal to 6 mu.
00:13
And the first question we have to find the equivalent capacitance.
00:19
Let us first give points like a and b, b and d.
00:28
The equivalent resistance between a and b is a series connection of the.
00:34
Two capacitors so we will write c1 .2 will be equal to c1 1 by c2 to the power minus 1.
00:49
And we will get the value of c12 will be equal to we have 9 divided by 4 mu f, which is equal to around 2 .25 nu f.
01:10
Now we have to do the equivalent resistance with now c1 and c3.
01:19
So let us write that as c equivalent equal to c1, 2, which will be c1 2 plus c3.
01:33
This is the formula for 5 -1 connection and will we get the equivalent to be equal to 8 .25 new f.
01:45
Now we have to find the charge and voltage drop across each capacitor when a 12 .5 voltage is applied.
01:59
So here 12 .5 voltage applied across these two terminals...