00:01
Hello, projectile was fired from the initial height of 1 .138 meters above the floor and it was fired at an angle 0 degree to the horizontal.
00:12
Basically it means that it was fired horizontally.
00:23
And here we have to determine speed of the projectile be 0 given the fact that the length of the flight is 9 .81, 2 .981 meters.
00:37
So that's question 1.
00:39
Here this motion occurs under gravity only.
00:41
That's why this l is v0 times time of light.
00:45
And time of the flight is square root of 2 .y0 over g.
00:50
Therefore, we can determine v0, that is l times square root of g over 2 .y0.
00:57
Let's calculate it.
01:08
And let's complete this calculation.
01:21
That is 6 .1857.
01:24
Or 6 .186 meters per second.
01:31
That is solved.
01:31
Now let's answer question two.
01:33
Here project tile was fired from the same height, but now at the angle tet of 59 degrees.
01:40
And we have to determine how far horizontally it goes.
01:42
So we have to calculate l...