00:01
Hello students in this question first we have to draw the schematic representation for the given condition.
00:08
Here the three engines which are operating at different temperature.
00:20
One with 400 kelvin temperature 300 kelvin and 200 kelvin.
00:39
One engine is operated between 400 and 300 kelvin and the second.
00:46
Engine is operated between 300 and 200 and synchronized with the first one.
00:52
Therefore, this is the schematic representation for the working of this engine.
00:59
Here, amount of heat, that is 1 ,200 joules is taken from the first reservoir and 100 joules of heat is given to the third reservoir which is working at 200 kelvin, which is q3.
01:21
This now we have to calculate amount of heat at 300 kelvin so net heat exchanged per cycle with 300 kelvin reservoir is the difference between the heat extracted from 400 and heat rejected to the 200 kelvin reservoir therefore q2 is equal to q1 minus q3 amount of heat taken is 1 ,000 minus 100 which is 100 ,000 joules.
02:04
Next we have to calculate total work done.
02:15
Total work done is the sum of the work done by two engines.
02:21
That is w is equal to w1 plus w2.
02:27
In order to calculate w1 and w2, we have efficiency.
02:34
As this engine is synchronized, efficiency is the same...